For future reference:
ack "term_one" * -l | xargs -n1 --replace sed -i 's/term_one/term_two/' {}
RHEL 4/5, IIRC don’t require “-n1″ and “–replace”.
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For future reference:
ack "term_one" * -l | xargs -n1 --replace sed -i 's/term_one/term_two/' {}
RHEL 4/5, IIRC don’t require “-n1″ and “–replace”.
Grep is great, but ack is even better!
Thanks for the solution. That’s what I was looking for.